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`"If "xy+y^(2)=tan x + y," then find "(dy)/(dx).` |
Answer» The given relation is `xy+y^(2)=tan x + y.` Differentiating both sides with respect to x, we get `(d)/(d)(xy)+(d)/(dx)(y^(2))=(d)/(dx(tan x) +(dy)/(dx)` `"or "[y.1+x.(dy)/(dx)]+2y(dy)/(dx)=sec^(2) x+(dy)/(dx)` |
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