InterviewSolution
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InterviewSolution
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`"If "y= sin x +e^(x)," then "(d^(2)x)/(dy^(2))=`A. `(-sin x +e^(x))^(-1)`B. `(sin x - e^(x))/((cos x +e^(x))^(2))`C. `(sin x - e^(x))/((cos x +e^(x))^(3))`D. `(sin x + e^(x))/((cos x +e^(x))^(3))` |
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Answer» `y=sin x +e^(x)or (dy)/(dx)=cos x +e^(x)` `"or "(dx)/(dy)=(cos x +e^(x))^(-1)" (1)"` `therefore" "(d^(2)x)/(dy^(2))=-(cos x +e^(x))^(-2)(-sin x +e^(x))(dx)/(dy)` Substituting the value of `(dy)/(dx)` from (1), `(d^(2)x)/(dy^(2))=((sin x -e^(x)))/((cos x +e^(x))^(2))(cos x +e^(x))^(-1)=(sin x-e^(x))/((cos x +e^(x))^(3))` |
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