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`" If "y=sqrt(logx+sqrt(logx+sqrt(logx+...oo)))," then "(dy)/(dx)` isA. `(x)/(2y-1)`B. `(x)/(2y+1)`C. `(1)/(x(2y-1)`D. `(1)/(x(1-2y)` |
Answer» `y=sqrt(log x+y)` `"or "y^(2)=log x+y` `"or "2y(dy)/(dx)=(1)/(x)+(dy)/(dx)or (dy)/(dx)=(1)/(x(2y-1))` |
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