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`"If "y^(x)=x^(y)," then find "(dy)/(dx).` |
Answer» Correct Answer - `(y(x log y-y))/(x(y log x -x))` `y^(x)=x^(y)` `"or "log y^(x)= log x^(y)` `"or "x log y = y log x` `"or "x(1)/(y)(dy)/(dx)+log y xx1 =(y)/(x)+log x (dy)/(dx)` `"or "((x)/(y)-log x)(dy)/(dx)=(y)/(x)-log y` `"or "(dy)/(dx)=(y/x-logy)/((x)/(y)-log x)=(y(y-x log y))/(x(x- y log x))=(y(x log y - y ))/(x(y log x -x))` |
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