In a 2.5 L flask at 27^(@)C temperature, thepressure of a gas was found to be8 atm. If41 xx 10^(23) molecules of thesame gas are introduced into thecontainer, thetemperature changed toT_(2).Thepressure of gas is found to be 10 atm. Find out thevalue ofT_(2).

In a 2.5 L flask at 27^(@)C temperature, thepressure of a gas was foun

1.	In a 2.5 L flask at 27^(@)C temperature, thepressure of a gas was found to be8 atm. If41 xx 10^(23) molecules of thesame gas are introduced into thecontainer, thetemperature changed toT_(2).Thepressure of gas is found to be 10 atm. Find out thevalue ofT_(2).
Answer» 253 K 347 K 230 K 370 K Solution :`6.023 xx 10^(23)` molecules CORRESPOND to 1 mole` 2.41 xx 10^(23) ` molecules correspond to ? ` = (2.41 xx 10^(23) ) / (6.023 xx 10^(23)) = 0.4`moles Case (i) `._(1)V_(1) = n_(1).R_(1).""T_(1)` ` 8.(2.5) = n_(1)(0.08).(300)` `n_(1) = (8(2.5))/((0.08)(300))` ` n_(1) = 0.833` moles Total moles, `n_(2) = 0.833 + 0.4` ` n_(2) = 1.233` Case (II) ` P_(2)V_(2) = n_(2)R T_(2)` ` 10(2.5) = 1.233 (0.08). T_(2)` `T_(2) = 253.4` K