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In ` A B C ,`if `(sinA)/(csinB)+(sinB)/c+(sinC)/b=c/(a b)+b/(a c)+a/(b c),`then the value of angle `A`is`120^0`(b) `90^0`(c) `60^0`(d) `30^0` |
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Answer» `sinA/(csinB)+(sinB)/C+sinC/b=c/(ab)+b/(ac)+a/(bc)` Sine law `sinA/a=sinB/b=sinC/a=k` `SinA=ak` `SinB=bk` `SinC=ck` `(ak)/(cbk)+(bk)/(c)+(ck)/b=c/(ab)+b/(ac)+a/(bc)` `k[b/c+c/b]=1/a[c/b+b/c]` `k=1/a` `sinA=ak` `sinA=a*1/a` `SinA=1` `A=90`. |
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