1.

In a certain gas, a source produces 40,000 compression and 40,000 rarefaction pulses in 1 sec. When the second compression pulse is produced, the first is 1cm away from the source. Calculate the wave speed.

Answer»

Solution :We know frequency is equal to number of COMPRESSION or rarefaction pulses travelled per second, hence frequency `(UPSILON)=40,000` HZ
Wave length `(lambda)=` distance between two consecutive compression or rarefaction pulses.
`lambda=1` CM
From `v= upsilon lambda = 40,000 Hz xx 1 cm= 40,000 cm//s=400 m//s`


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