1.

In a circuit if two resistors of 4 Omega and 8 Omegaare connected in parallel, find out the ratio of current passing through the two resistors.

Answer»

Solution :`R_(1)=4 Omega`
`R_(2) Omega`
Potential DIFFERENCE =V
`I_(1) = (V)/(R_(1))=(V)/(4Omega)`
`I_(2)= (V)/(R_(2))=(V)/(8 Omega)`
`(I_(1))/(I_(2))= (V//4)/(V//8)`
or `(I_(1))/(I_(2))=(8)/(4)`
or `(I_(1))/(I_(2))=(2)/(1)`
`:. I_(1): I_(2)= 2:1`


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