1.

In a dam,water falls at a rate of 1000 kg s^(-1) from a height of 100 m . (b)Assuming that 60% of the energy of the falling water is converted to electrical energy,Calculate the power generated (Take g=9.8 m s^(-2))

Answer»

Solution :Given :in ONE second 1000 kg of WATER falls.
i.e., m=1000 kg ,t=1s, g=9.8 `MS^(-2)`,h=100 m .
(a)Initial potential energy of water =MGH (b)Energy available from the falling water Energy converted to electrical energy Power generated =`("Electrical energy")/("Time")(0.6 mgh)/(t)`
=`(0.6xx1000xx9.8xx100)/(1)J s^(-1)`
`5.88xx10^(5)W`


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