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In a parallel RL circuit, 10 A current enters into the resistor R and 15 A current enters into the Inductor L. The total current I is _____________(a) 15.5 A(b) 25.05 A(c) 18.03 A(d) 30.15 AThis question was addressed to me in homework.The above asked question is from Advanced Problems on Filters in portion Filters and Attenuators of Network Theory

Answer»

The CORRECT ANSWER is (c) 18.03 A

Explanation: Currents in RESISTANCE and inductance are out of PHASE by 90°.

Hence, I = \(I_1^2 + I_2^2\)

Or, I = [10^2 + 15^2]^0.5

Or, I = \(\sqrt{100+225} = \sqrt{325}\)

= 18.03 A.



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