1.

In a photoelectric effect experiment irradiation of a metal with light of frequency `5.2 xx 10^(14) s^(-1)` yields elctrons with maximum kinetic ennergy `1.3 xx 10^(-19) J`.Calculate the threshold frequency `(v_(0))` for the metal

Answer» We know that
`hv = hv_(0)+ KE`
or `v_(0) = v - (KE)/(h)`
`KE = 1.3 xx 10^(-19)J, v = 5.2 xx 10^(14)s^(-1), h = 6.626 xx 10^(-34) Js`
:. Theshold frequency
`v_(0) = 5.2 xx 10^(24)s^(-1) - (1.3 xx 10^(19)J)/(6.626 xx 10^(-34)Js)`
`= 5.2 xx 10^(14)s^(-1) - 1.96 xx 10^(14)s^(-1)`
`3.24 xx 10^(14) s^(-1)`


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