InterviewSolution
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InterviewSolution
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In air , a charged soap bubble of radius r is in equilibrium having outside and inside pressures being equal . The charge on the drop is (`epsi_(0)` = permittivity of free space , T = surface tension of soap solution)A. `4 pi r^(2) sqrt((2 T epsi_(0))/(t))`B. `4 pi r^(2) sqrt((4 E epsi_(0))/(t))`C. `4 pi r^(2) sqrt((6 T epsi_(0))/(t))`D. `4 pi r^(2) sqrt((8 T epsi_(0))/(t))` |
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Answer» Correct Answer - D For a charged soap bubble `P_("external") + P_("electro") = (4T)/(r)` In equilibrium condition Surface charge density `sigma` is given by `sigma^(2) = (E epsi_(0)T)/(r) implies sigma = sqrt((8 epsi_(0) T)/(r))` `(q)/(4 pi r^(2)) = sqrt((8 epsi_(0)T)/(r)) implies theta = 4 pi rho^(2) sqrt((8 epsi_(0) T)/(rho))` |
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