The relation between force `F` and density `d` is `F=(x)/(sqrt(d))`. The dimension of `x` isA. `[L^(-1//2) M^(3//2) T^(-2)]`B. `[L^(-1//2) M^(1//2) T^(-2)]`C. `[L^(-1) M^(3//2) T^(-2)]`D. `[L^(-1) M^(1//2) T^(-2)]`

The relation between force `F` and density `d` is `F=(x)/(sqrt(d))`. T

1.	The relation between force `F` and density `d` is `F=(x)/(sqrt(d))`. The dimension of `x` isA. `[L^(-1//2) M^(3//2) T^(-2)]`B. `[L^(-1//2) M^(1//2) T^(-2)]`C. `[L^(-1) M^(3//2) T^(-2)]`D. `[L^(-1) M^(1//2) T^(-2)]`
Answer» Correct Answer - A Given `, F = (x)/(sqrtd)` Substituting dimensions `MLT^(2) = (x)/(sqrt(ML^(-3)))` `implies x = [M^(3//2) L^(-1//2) T^(2)]`

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The relation between force `F` and density `d` is `F=(x)/(sqrt(d))`. The dimension of `x` isA. `[L^(-1//2) M^(3//2) T^(-2)]`B. `[L^(-1//2) M^(1//2) T^(-2)]`C. `[L^(-1) M^(3//2) T^(-2)]`D. `[L^(-1) M^(1//2) T^(-2)]`

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