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In common base circuit of a transistor , current amplification factor is `0.95`. Calculate the emitter current , if base current is `0.2` mAA. 2 mAB. 4 m AC. 6 mAD. 8 mA |
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Answer» Correct Answer - B Given `alpha = 0.95 , I_(b) = 0.2` mA As `" " alpha = (I_(c))/(I_(e)) = (I_(e) - I_(b))/(I_(e)) = 1 - (I_(b))/(I_(e))` `implies (I_(b))/(I_(e)) = 1 - alpha = 1- 0.95` `implies (I_(b))/(I_(e)) = 0.5 implies (0.2)/(0.05) mA = I_(e)` `implies I_(e) = 4 mA` |
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