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The angle `theta` between the vector `p=hati+hatj +hatk` and unit vector along X-axis isA. `cos^(-1) ((1)/(sqrt3))`B. `cos^(-1) ((1)/(sqrt2))`C. `cos^(-1) ((sqrt3)/(2))`D. `cos^(-1)((1)/(2))` |
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Answer» Correct Answer - A The angle between `p = hati + hatj + hatk ` `x -` axis ` x = hati` is given by `cos theta = (p * x)/(|p||x|) = ((hati + hatj + hatk))/(sqrt(1^(2) + 1^(2) + 1^(2)))((hati))/(sqrt(1^(2))) = (1)/(sqrt3)` `implies theta = cos^(-1) ((1)/(sqrt3))` |
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