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In all, how many nodal plates are there in the atomic orbiitals for the principal quantum number `n = 3`? |
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Answer» Shell with `n = 3` has ` 1s (3s),3p(p_(x)p_(y)p_(z)) ` and `5d(d_(xy)d_(z)d_(y^(2) - y^(3)) ` and ` d_(z^(2)` x has no nodal plane Each of `p_(x)p_(y)p_(z)` has one nodel palne means a total of three nodal plases `d_(z^(2)` has no nodal palne Each of `d_(xy)d_(xz) d_(x)d_(x^(2) - y^(2)` has nodal plases Hence for `n = 3` a total of nodal planes are there . |
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