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In an instrument, there are 25 divisions on the vernier scale which have length of 24 divisions of the main scale. 1 cm on main scale is divided in 20 equal parts. Find the least count. |
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Answer» SOLUTION :The value of one main scale DIVISION x = `1/(20)` CM The number of divisions on vernier scale n=25 `therefore ` L.C. of vernier `=("Value of one main scale division (x)")/("Number of divisions on vernier scale (n)")` `=((1//20)cm)/(25) = 1/(500) cm = 0.002 cm` |
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