1.

In an instrument, there are 25 divisions on the vernier scale which have length of 24 divisions of the main scale. 1 cm on main scale is divided in 20 equal parts. Find the least count.

Answer»

SOLUTION :The value of one main scale DIVISION x = `1/(20)` CM The number of divisions on vernier scale n=25
`therefore ` L.C. of vernier
`=("Value of one main scale division (x)")/("Number of divisions on vernier scale (n)")`
`=((1//20)cm)/(25) = 1/(500) cm = 0.002 cm`


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