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In any triangle ABC, if `a=18 , b=24 , c=30`, findcosA, cosB, cosC

Answer» Here, `30^2 = 18^2+24^2`
That means triangle ABC is aright angle triangle with `/_C = 90^@`
With the given details,`cosA = (AC)/(AB) = b/c = 24/30 = 4/5`
`cosB = (BC)/(AB) = a/c = 18/30 = 3/5`
`cosC = cos90^@ = 0`


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