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In any triangle ABC, if `a= 18 , b= 24 , c= 30`, findsinA, sinB, sinC

Answer» Here, `30^2 = 18^2+24^2`
That means triangle ABC is aright angle triangle with `/_C = 90^@`
With the given details,`sinA = (BC)/(AB) = a/c = 18/30 = 3/5`
`sinB= (AC)/(AB) = b/c = 24/30 = 4/5`
`sinC = sin90^@ = 1`


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