1.

In ΔPQR, ∠P + ∠Q = ∠R, PR = 6 and QR = 8, then PQ = ?1). 102). 153). 184). 20

Answer»

SUM of the three ANGLE of triangle is 180°

∠P + ∠Q + ∠R = 180°

∠R + ∠R = 180°

2∠R = 180°

∠R = 90°

So, PQ is hypotenuse

As PER Pythagoras THEOREM,

PQ2 = PR2 + QR2

= 36 + 64

PQ2 = 100

PQ = 10



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