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In ΔPQR, ∠P + ∠Q = ∠R, PR = 6 and QR = 8, then PQ = ?1). 102). 153). 184). 20 |
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Answer» SUM of the three ANGLE of triangle is 180° ∠P + ∠Q + ∠R = 180° ∠R + ∠R = 180° 2∠R = 180° ∠R = 90° So, PQ is hypotenuse PQ2 = PR2 + QR2 = 36 + 64 PQ2 = 100 PQ = 10 |
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