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In order to prepare `100cm^(3)` of `0.250M` barium chloride solution, the amount of `BaCI_(2).2H_(2)O` required will beA. 0.250 molesB. .0025 molesC. 2.5 molesD. `6.1g` of `BaCI_(2).2H_(2)O` |
Answer» Correct Answer - D Amount of `BaCI_(2).2H_(2)O` required `= (1"mole")/(1000) xx 100 xx 0.2` moles `= 0.025 xx 224 = 6.1g` |
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