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In `psi_(321)` the sum of angular momentum, spherical nodes and angular node is:A. `(sqrt(6)h+4pi)/(2pi)`B. `(sqrt(6h))/(2pi)+3`C. `(sqrt(6h)+2pi)/(2pi)`D. `(sqrt(6h)+8pi)/(2pi)` |
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Answer» Correct Answer - A `psi_(321): n = 3, i=2, m= 1` Angular momentum `=(h)/(2pi) sqrt(l(l+1)) = (sqrt(6)h)/(2pi)` Spherical nodes `= 3 - 2 -1 = 0`, Angular node `=2` Sum of all the above `=(sqrt(6)h)/(2pi) +2 = (sqrt(6h)+4pi)/(2pi)` |
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