In Q 64 above , suppose the cable breaks , then the weighing machine w

1.	In Q 64 above , suppose the cable breaks , then the weighing machine will read
Answer» more than the weight of the body less than the weight of the body equalto the weight of the body zero Solution :Whena PERSON of maas M is standing on a weighing machine placed in a lift , the actual weight of the person =Mg This weight ACTS on the weighing machine which offers a reaction R, given by the READING of the weighing machine. (i)When the elevator is at rest or moving with uniform velocity , upwards or downwards , apparent weight R = mg , which is the actual weight . (ii)When the elevator is accelerating downwards with ACCELERATION a , we have mg - R =ma or R= m(g-a) In this case , apparent weight becomes less. (iii) When the elevator is accelerating upwards with acceleration a , we have R- mg=ma or R=m(g+a) In this case , apparent weight becomes more . (iv)If a=g,R=m(g-g)=0 So , the apparent weight of a person in an elevator falling down FREELY with an acceleration (=g) is zero .

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