

InterviewSolution
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In quantum mechanics, the energy associated by a wave particle E is given as1. \(\hbar k\)2. \(2\hbar k\)3. \(2\hbar \omega\)4. \(\hbar \omega\) |
Answer» Correct Answer - Option 4 : \(\hbar \omega\) Correct option-4 Concept:
Calculation: In quantum mechanics, a quantum particle in a given system is treated as a wave-particle. Actually, they are assumed as wave packets which is a linear combination of several waves that interfere constructively. The energy associated with such wave-particle is given by- \(E=h\vartheta \) ----(i) Since\(\vartheta =\frac{ω }{2\pi }\) ----(ii) where, ω is the angular frequency On substituting the given value of\(\vartheta\)from equation (ii) in equation (i), we get \(E=h\frac{ω }{2\pi }=\hbar ω \) Here\(\hbar =\frac{h}{2\pi }\) \(\therefore E=\hbar ω \) Thus, option-4is the correct answer. |
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