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Specific heat of water is 4.2 J/g°C. If light of frequency 2 ×109 Hz is used to heat 500 gm of water from 30°C to 50°C, the number of photons needed will be1. 1.69 × 10292. 3.2 × 10283. 2.80 × 1044. 2.80 × 105 |
Answer» Correct Answer - Option 2 : 3.2 × 1028 CONTENT: Specific heat:
⇒Q = mC∆t -----(1) Where Q(J) = quantity of heat absorbed by a body, m(kg) = mass of the body, ∆t(°K) = Rise in temperature, and C = Specific heat
Photon:
⇒ E = hν Where, h = Planck's constant, and ν= frequency CALCULATION: Given (Specific heat) C= 4.2J/gº-C, (mass) m = 500 g, T1= 30° C,T2= 50° C, and(frequency) ν =2×109 Hz
⇒ E = hν ⇒ E =6.6 × 10-34× 2 × 109 ⇒ E = 13.2 × 10-25J -----(1)
⇒ΔT =T2- T1 ⇒ΔT = 50 - 30 ⇒ΔT = 20°C
⇒ Q = mCΔT ⇒ Q = 500 × 4.2 × 20 ⇒ Q = 42000 J -----(2)
⇒ NE = Q \(⇒ N=\frac{42000}{13.2×10^{-25}}\) ⇒ N =3.2 × 1028
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