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In photoelectric emission process from a metal of work function 1.8 eV, the kinetic energy of most energeticelectric electrons is 0.5 eV. The corresponding stopping potential is1. 2.3 V2. 1.8 V3. 1.3 V4. 0.5 V |
Answer» Correct Answer - Option 4 : 0.5 V CONCEPT: Photoelectric Effect:
⇒KEmax= hν-ϕo Where h = Planck's constant,ν = frequency of incident radiation, ϕo= work function, and KE =maximum kinetic energy of electrons.
⇒KE = qV0 Where KE = Kinetic energy, q = charge, V0= Stopping potential CALCULATION: Given -KEmax= 0.5 eV , e = 1.6 × 10-19C
⇒KEmax= eV0 Substituting the given values in the above equation ⇒0.5eV = 1.6 × 10-19× V0 \(\Rightarrow V_{0} = \dfrac{0.5\times 1.6\times 10^{-19}}{1.6\times 10^{-19}} = 0.5V\)
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