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IN radioactive series, an inner transition element `._(92)U^(238)` loses one `alpha`-particles and one `beta`-particle to produce a very unstable daughter nuclei `._(91)Pa^(234)` with half life 1.14 min. Find out the displacement in group due to these emissions. |
Answer» The reaction is: `._(92)U^(238) overset(-alpha)rarr ._(90)Th^(234) overset(-beta)rarr ._(91)Pa^(234)` Since elements from `._(89)Ac` to `._(103)Lw` exist is the same group, where as from `._(90)Th` to `._(103)Lw` are inner transition elements of actinium series, so group will not change. In this case, group displacement law is not valid. The daughter element will be in same group `III B`. |
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