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In single-phase, RLE load, calculate the Peak inverse voltage using the data: (Vs)r.m.s = 9 V, f = 50 Hz,E = 40 V.(a) 52.2 V(b) 52.7 V(c) 59.7 V(d) 52.9 VI have been asked this question during an interview for a job.This interesting question is from Electrical Drive Systems and Components in division Electrical Drive Systems and Components of Electric Drives

Answer»

Right answer is (b) 52.7 V

Explanation: In a single PHASE, RLE load the peak inverse VOLTAGE ACROSS the THYRISTOR VT = Vm+E = 52.7 V.



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