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In the circuit given below, bulb X uses 48 W when lit, bulb Y uses 22 W when lit and bulb Z uses 14.4 W when lit. The number of additional bulbs in parallel to this circuit, that would be required to below the fuse is _______________(a) 4(b) 5(c) 6(d) 7I have been asked this question in an interview for job.The query is from Problems Involving Dot Conventions in portion Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

The correct answer is (a) 4

The best explanation: IX = \(\frac{48}{12}\) = 4 A

IY = \(\frac{22}{12}\) = 1.8 A

IZ = \(\frac{14.4}{12}\) = 1.2 A

CURRENT REQUIRED to below the fuse = 20 A

∴ Additional BULBS must draw current = 20 – (4 + 18 + 1.2)

= 20 – 7 = 13

∴ Number of additional bulbs required = \(\frac{13}{3}\) = 4.33

So, 4 additional bulbs are required.



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