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In the circuit given below, it is given that VAB = 4 V for RL = 10 kΩ and VAB = 1 V for RL = 2kΩ. The value of Norton resistance for the network N is ____________(a) 16 kΩ(b) 30 kΩ(c) 3 kΩ(d) 50 kΩThe question was posed to me by my college director while I was bunking the class.My question is from Norton’s Theorem Involving Dependent and Independent Sources in section Useful Theorems in Circuit Analysis of Network Theory

Answer»

Right ANSWER is (b) 30 kΩ

The best I can EXPLAIN: When RL = 10 kΩ and VAB = 4 V

Current in the circuit \(\frac{V_{AB}}{R_L} = \frac{4}{10}\) = 0.4 mA

Norton voltage is given by VN = I (RN + RL)

= 0.4(RN + 10)

= 0.4RN + 4

Similarly, for RL = 2 kΩ and VAB = 1 V

So, I = \(\frac{1}{2}\) = 0.5 mA

VN = 0.5(RN + 2)

= 0.5 RN + 1

∴ 0.1RN = 3

Or, RN = 30 kΩ.



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