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In the circuit given below, the equivalent capacitance is ____________(a) 1.625 F(b) 1.583 F(c) 0.583 F(d) 0.615 FThe question was asked by my college professor while I was bunking the class.The above asked question is from Problems Involving Dot Conventions in division Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

The CORRECT CHOICE is (d) 0.615 F

Best EXPLANATION: CCB = \(\left(\FRAC{C_2 C_3}{C_2+ C_3}\RIGHT)\) + C5 = 1.5 F

Now, CAB =\(\left(\frac{C_1 C_{CB}}{C_1+ C_{CB}}\right)\) + C6 = 1.6 F

CXY = \(\frac{C_{AB}× C_4}{C_{AB} + C_4}\) = 0.615 F.



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