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In the circuit given below, the equivalent capacitance is ______________(a) 3.5 μF(b) 1.2 μF(c) 2.4 μF(d) 4.05 μFI got this question by my college director while I was bunking the class.This interesting question is from Problems Involving Dot Conventions in chapter Resonance & Magnetically Coupled Circuit of Network Theory |
Answer» CORRECT choice is (d) 4.05 μF To elaborate: The 2.5 μF capacitor is in PARALLEL with 1 μF capacitor and this COMBINATION is in series with 1.5 μF. Hence, C1 = \(\frac{1.5(2.5+1)}{1.5+2.5+1}\) = \(\frac{5.25}{5}\) = 1.05 Now, C1 is in parallel with the 3 μF capacitor. ∴ CEQ = 1.05 + 3 = 4.05 μF. |
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