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In the circuit given below, the phasor voltage VAB (in volt) is _________(a) Zero(b) 5∠30°(c) 12.5∠30°(d) 17∠30°I had been asked this question during an online exam.My doubt stems from Advanced Problems on Network Theorems topic in portion Useful Theorems in Circuit Analysis of Network Theory

Answer» RIGHT choice is (d) 17∠30°

To explain I would say: Equivalent impedance = (5 + J3) || (5 – √3)

= \(\frac{(5+j3)×(5 – \sqrt{3})}{(5+j3) + (5 – \sqrt{3})} \)

= \(\frac{25+9}{10}\) = 3.4 Ω

VAB = Current × Impedance

= 5∠30° × 3.4

= 17∠30°.


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