

InterviewSolution
Saved Bookmarks
1. |
In the circuit given below, the phasor voltage VAB (in volt) is _________(a) Zero(b) 5∠30°(c) 12.5∠30°(d) 17∠30°I had been asked this question during an online exam.My doubt stems from Advanced Problems on Network Theorems topic in portion Useful Theorems in Circuit Analysis of Network Theory |
Answer» RIGHT choice is (d) 17∠30° To explain I would say: Equivalent impedance = (5 + J3) || (5 – √3) = \(\frac{(5+j3)×(5 – \sqrt{3})}{(5+j3) + (5 – \sqrt{3})} \) = \(\frac{25+9}{10}\) = 3.4 Ω VAB = Current × Impedance = 5∠30° × 3.4 = 17∠30°. |
|