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In the circuit given below, the switch S1 is initially closed and S2 is opened. The inductor L carries a current of 10A and the capacitor is charged to 10 V with polarities as shown. The current through C during t=0^+ is _____________(a) 55 A(b) 5.5 A(c) 45 A(d) 4.5 AI had been asked this question at a job interview.This is a very interesting question from Dot Convention in Magnetically Coupled Circuits in portion Resonance & Magnetically Coupled Circuit of Network Theory

Answer» CORRECT option is (d) 4.5 A

The explanation is: By KCL, we get,

\(\frac{V_L}{10} – 10 + \frac{V_L-10}{10}\) = 0

Hence, 2 VL = 110

∴ VL = 55 V

Or, IC = \(\frac{55-10}{10}\) = 4.5 A.


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