1.

In the circuit shown below, I1 = 4 sin2t A and I2 = 0. The value of V1 is _______________(a) -16 cos2t V(b) 16 cos2t V(c) 4 cos2t V(d) -4 cos2t VThis question was addressed to me during an online exam.Origin of the question is Advanced Problems on Magnetically Coupled Circuits in division Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

The correct option is (B) 16 cos2t V

Explanation: V1 = \(\frac{2dI_1}{DT} + \frac{1dI_2}{dt}\)

∴ V1 = \(\frac{2dI_1}{dt}\) = 16 cos2t V.



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