1.

In the circuit shown in fig. `C_1 = 2C_2` Initially, capacitor `C_1` is charged to a potential of V. The current in the circuit just after the switch S is closed is

Answer» Correct Answer - D
Here, `I_(1) = (V)/(R )e^(-t//RC), I_(2) = (V)/(R )e^(-t//2RC)`
`:. (I_(1))/(I_(2))=e^(-t//RC +t//2RC) = e^(-t//2RC) = (1)/(e^(t//2RC)`
From this expression, it is clear that when t increases, ratio
decrease.


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