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In the circuit shown in fig. `C_1 = 2C_2` Initially, capacitor `C_1` is charged to a potential of V. The current in the circuit just after the switch S is closed is |
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Answer» Correct Answer - D Here, `I_(1) = (V)/(R )e^(-t//RC), I_(2) = (V)/(R )e^(-t//2RC)` `:. (I_(1))/(I_(2))=e^(-t//RC +t//2RC) = e^(-t//2RC) = (1)/(e^(t//2RC)` From this expression, it is clear that when t increases, ratio decrease. |
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