1.

In the circuit shown in fig. the cell is ideal with emf 15V. Each resistance is of `3Omega.` The potential difference across the capacitoro in steady state is

Answer» Correct Answer - C
As the capacitors are identical, each of them finally have
chargel Q//2.
Initial energy of the system in `E_(1) = (Q^(2))/(2C)`
Final energy of the system is `E_(f)=2[((Q//2)^(2))/(2C)]=(Q^(2))/(4C)`
Heat produced = loss in energy `=E_(i) - E_(f) = (Q^(2))/(4C)`


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