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In the circuit shown power dissipated in 12 Omegaresistance is 6 watt. What is the power dissipated in the 8 Omega resistance. |
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Answer» SOLUTION :In PARALLEL arrangement voltage V remains same and `P_1/P_2=R_2/R_1` `THEREFORE ` Power in `8 Omega` resistance `P_2=(P_1R_1)/R_2=(6 times 12)/8=9W`
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