1.

In the circuit shown power dissipated in 12 Omegaresistance is 6 watt. What is the power dissipated in the 8 Omega resistance.

Answer»

SOLUTION :In PARALLEL arrangement voltage V remains same and `P_1/P_2=R_2/R_1`
`THEREFORE ` Power in `8 Omega` resistance `P_2=(P_1R_1)/R_2=(6 times 12)/8=9W`


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