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In the circuit shwon in fig. switch S is closed at time t = 0. Let `I_1 and I_2` be the currents at any finite time t, then the ratio `I_1// I_2` A. is constantB. increases with timeC. decreases with timeD. first increases, then decreases |
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Answer» Correct Answer - C `I = I_(0)e^(-t//RC) or (I_(0))/(2) = I_(0)e^(-t//RC) or t = RC in 2` or `10^(-6) xx In4 =(2+r)xx0.5xx10^(-6)In 2` Solving to get `r = 2 Omega` |
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