In the electrolysis of water: (i) Name the gas collected at the cathode and anode respectively . (ii) Why is the volume of one gas collected at oneelectrode is double than that at the other ? Name this gas . (iii) How will you test the evolved gases?

In the electrolysis of water: (i) Name the gas collected at the catho

1.	In the electrolysis of water: (i) Name the gas collected at the cathode and anode respectively . (ii) Why is the volume of one gas collected at oneelectrode is double than that at the other ? Name this gas . (iii) How will you test the evolved gases?
Answer» Solution :(i) At Cathode : hydrogen gas `(H_(2))` At Anode: oxygen gas `(O_(2))` (II) Since, `2H_(2)O overset ("Electric current ")rarr 2H_(2)+O_(2)` 2 MOLECULES of `H_(2)O`, so the volume of `H_(2)` liberated is double that of `O_(2)` (iii) When a burning SPLINTER is brought near the mouth of the liberated gases, the burning splinter extinguishes near the `H_(2)` gas while the burning splinter keeps burning more near the `O_(2)` gas.