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In the figure, AB = DE, BC = EF and AC = DF. Can ∠BPD = ∠C? Prove it? |
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Answer» The sides of ∆ DEF and ∆ ABC are equal. The angles opposite to equal sides are equal. ∠E = ∠B, ∠F = ∠C, ∠D = ∠A But ∠C = 180 – (∠B + ∠A) ∠P = 180 – (∠B + ∠D) ∴ ∠D = ∠A ∴ ∠C = ∠P = 180 – (∠B + ∠A) ∴ ∠C = ∠P |
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