1.

In the figure, AB = DE, BC = EF and AC = DF. Can ∠BPD = ∠C? Prove it?

Answer»

The sides of ∆ DEF and ∆ ABC are equal. The angles opposite to equal sides are equal.

∠E = ∠B, ∠F = ∠C, ∠D = ∠A

But ∠C = 180 – (∠B + ∠A)

∠P = 180 – (∠B + ∠D)

∴ ∠D = ∠A

∴ ∠C = ∠P = 180 – (∠B + ∠A)

∴ ∠C = ∠P



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