1.

O is the centre of the circle in the diagram. Radius is 3 cm and ∠AOB = 60°. Find the perimeter of ∆ AOB?

Answer»

∆ OAB is an isosceles triangle.

∴ ∠A =∠B

∠O = 60

∴ ∠OAB is an equilateral triangle so perimeter = 3 + 3 + 3 = 9 cm.



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