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O is the centre of the circle in the diagram. Radius is 3 cm and ∠AOB = 60°. Find the perimeter of ∆ AOB? |
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Answer» ∆ OAB is an isosceles triangle. ∴ ∠A =∠B ∠O = 60 ∴ ∠OAB is an equilateral triangle so perimeter = 3 + 3 + 3 = 9 cm. |
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