1.

In the figure given below, a 220 V 50 Hz supplies a 3-phase balanced source. The pressure Coil (PC) and Current Coil (CC) of a watt-meter are connected to the load as shown. The watt-meter reading is _________(a) Zero(b) 1600 W(c) 242 W(d) 400 WThe question was posed to me in an interview for internship.The above asked question is from Problems Involving Coupling Coefficient in chapter Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

The correct OPTION is (c) 242 W

Explanation: Watt-meter reading = CURRENT through CC × Voltage across PC × cos (phase angle).

IBR = ICC = \(\frac{220∠120°}{100°}\) = 2.2∠120°

VYB = VPC = 220∠-120°

w = 2.2∠120° × 220∠-120° × cos 240° = – 242 W.



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