1.

In the figure given, the position-time graph of a particle of mass 0.1 kg is shown the impulse at t = 2s is

Answer»

0.2 KG m/s
`-0.2` kg m/s
0.1 kg m/s
`-0.4` kg m/s

Solution :IMPULSE= CHANGE in MOMENTUM
=m(v-u)
=0.1 (0-2) `=-0.2"kg m/s"`


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