In the followingfigure , ABCis a righttrianglerightangledat A. BCEDACFGand ABMN and squareson the sidesBC,CA and ABrespectively , LinesegementAXbotDEmeetsBC at Y. Show that (i)tirangle MBC = tirangle (MBC) (ii) ar (BXYD) = 2 ar (MBC) (iii) ar (BYXD) = ar(ABMN)(iv)tirangle FCB = tirangle ACE (v)ar (CYXE) = 2 ar (FCB) (vi) ar (CYXE )= ar (ACFG) (vii)ar (BCED) = ar (ABMN) + ar (ACFG)

In the followingfigure , ABCis a righttrianglerightangledat A. BCEDACF

1.	In the followingfigure , ABCis a righttrianglerightangledat A. BCEDACFGand ABMN and squareson the sidesBC,CA and ABrespectively , LinesegementAXbotDEmeetsBC at Y. Show that (i)tirangle MBC = tirangle (MBC) (ii) ar (BXYD) = 2 ar (MBC) (iii) ar (BYXD) = ar(ABMN)(iv)tirangle FCB = tirangle ACE (v)ar (CYXE) = 2 ar (FCB) (vi) ar (CYXE )= ar (ACFG) (vii)ar (BCED) = ar (ABMN) + ar (ACFG)
Answer» Answer :(i) `ANGLE ABD ` (ii) `1/2` (iii) AMBN (iv) ` tirangle ACE ` (v) 2 (VI)ACFG ABMN