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In the given nuclear reaction `A, B, C, D, E` represents `._92 U^238 rarr^(alpha) ._BTh^A rarr^(beta) ._D Pa^C rarr^(E) ._92 U^234`.A. `A = 234, B = 90, C = 234, D = 91, E = beta`B. `A = 234, B = 90, C = 238, D = 94, E = alpha`C. `A = 238, B = 93, C = 234, D = 91, E = beta`D. `A = 234, B = 90, C = 234, D = 93, E =alpha` |
Answer» Correct Answer - A (a) `._92U^238 overset (alpha)rarr ._90Th^234 overset (beta)rarr ._91 Pa^234` `overset (E(._1beta^0))rarr ._92 U^234`. |
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