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In the ideal double-slit experiment, when a glass-plate (refractive index 1.5) of thickness t is introduced in the path of one of the interfering beams (wavelength `lambda`), the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass-plate isA. `2lambda`B. `2lambda//3`C. `lambda//3`D. `lambda` |
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Answer» Correct Answer - A `phi=(2pi)/lambdaDeltax=(2pi)/lambda(mu-1)t` `phi=0, 2pi, 4pi, …` `2pi=(2pi)/lambda(1.5-1)t implies t=2lambda` |
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