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A single slit of width `0.20 mm` is illuminated with light of wavelength `500 nm`. The observing screen is placed `80 cm` from the slit. The width of the central bright fringe will beA. `1 mm`B. `2 mm`C. `4 mm`D. `5 mm` |
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Answer» Correct Answer - C Width of central bright fringe`=(2Dlambda)/a` `=(2xx0.8xx500xx10^(-9))/(0.2xx10^(-3))=4xx10^(-3) m=4 mm` |
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