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A screen is placed 50cm from a single slit, which is illuminated with 6000Å light. If distance between the first and third minima in the diffraction pattern is 3.0 mm, what is the width of the slit? |
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Answer» `D=50 cm, lambda=600 nm` `y_(3)-y_(1)=(3Dlambda)/a=(Dlambda)/a=(2Dlambda)/a` `3xx10^(-3)=(2xx0.5xx600xx10^(-9))/a` `a=200xx10^(-6) m=0.2 mm` |
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