1.

A screen is placed 50cm from a single slit, which is illuminated with 6000Å light. If distance between the first and third minima in the diffraction pattern is 3.0 mm, what is the width of the slit?

Answer» `D=50 cm, lambda=600 nm`
`y_(3)-y_(1)=(3Dlambda)/a=(Dlambda)/a=(2Dlambda)/a`
`3xx10^(-3)=(2xx0.5xx600xx10^(-9))/a`
`a=200xx10^(-6) m=0.2 mm`


Discussion

No Comment Found

Related InterviewSolutions