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Light of wavelength `6328 Å` is incident normally on a slit having a width of `0.2 mm`. The distance of the screen from the slit is `0.9 m`. The angular width of the central maximum isA. `0.09^(@)`B. `0.72^(@)`C. `0.18^(@)`D. `0.36^(@)` |
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Answer» Correct Answer - D Angular width of central maximum `theta_(0)=(2lambda)/a=(2xx6328xx10^(-10))/(0.2xx10^(-3))=6.328xx10^(-3) rad` `=[(6.328xx10^(-3))xx180/pi]^(@)=0.36^(@)` |
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